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8a^2+6a=-5+14
We move all terms to the left:
8a^2+6a-(-5+14)=0
We add all the numbers together, and all the variables
8a^2+6a-9=0
a = 8; b = 6; c = -9;
Δ = b2-4ac
Δ = 62-4·8·(-9)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*8}=\frac{-24}{16} =-1+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*8}=\frac{12}{16} =3/4 $
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